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What is the peak value of a waveform with an effective value of 20.2 amps of AC current?

  1. 20.2 amps

  2. 24.5 amps

  3. 28.6 amps

  4. 32.0 amps

The correct answer is: 28.6 amps

The peak value of an alternating current (AC) waveform can be calculated using the effective (or root mean square, RMS) value. The relationship between the peak value (Vp) and the RMS value (Irms) for a sinusoidal waveform is given by the formula: \[ Vp = Irms \times \sqrt{2} \] In this case, the effective value of the AC current is 20.2 amps. Using the formula: \[ Vp = 20.2 \times \sqrt{2} \] \[ Vp = 20.2 \times 1.414 \] \[ Vp \approx 28.6 \text{ amps} \] Thus, the peak value of the waveform is approximately 28.6 amps. This calculation demonstrates that the peak current is greater than the effective current, reflecting the characteristics of AC waveforms where the peak value is typically about 1.414 times the effective value.