NEIEP Mechanics Practice Exam

Session length

1 / 680

What happens to the power consumed if you double the voltage across a resistor while keeping the resistance constant?

The power remains the same

The power is halved

The power is doubled

When the voltage across a resistor is doubled while keeping the resistance constant, the power consumed by the resistor increases significantly. This relationship is described by Ohm's Law and the power formula.

According to Ohm's law, the current (I) through a resistor can be calculated using the formula \( I = \frac{V}{R} \), where V is the voltage, and R is the resistance. The power (P) consumed in an electrical circuit can be represented by the formula \( P = V \times I \). Substituting Ohm's Law into the power formula gives \( P = V \times \frac{V}{R} \) or \( P = \frac{V^2}{R} \).

When you double the voltage (let’s say the original voltage is V, and you increase it to 2V), the new power consumption can be calculated as follows:

- Original power: \( P_1 = \frac{V^2}{R} \)

- New power after doubling voltage: \( P_2 = \frac{(2V)^2}{R} = \frac{4V^2}{R} \)

Comparing the new power and the original power shows that

Get further explanation with Examzify DeepDiveBeta

The power is quadrupled

Next Question
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy