NEIEP Mechanics Practice Exam

To find the total reactance in an AC circuit with a given inductor, the reactance of the inductor can be calculated using the formula:

\[ X_L = 2 \pi f L \]

where:

- \( X_L \) is the inductive reactance in ohms,

- \( f \) is the frequency in hertz,

- \( L \) is the inductance in henries.

Given that the frequency \( f \) is 60 Hz and the inductance \( L \) is 4 Henry, we can substitute these values into the formula:

1. Calculate \( 2 \pi f \):

\[

2 \pi \times 60 \approx 376.99 \, \text{rad/s}

\]

2. Now, multiply by the inductance \( L \):

\[

X_L = 376.99 \times 4 \approx 1507.96 \, \text{ohms}

\]

This value is typically rounded to 1507 ohms. This calculation reveals that the total reactance due to the 4 Henry inductor at a frequency of 60 Hz is approximately 1507 ohms, justifying