NEIEP Mechanics Practice Exam

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Question: 1 / 475

If the period of a sine wave is .0083 seconds, what is its frequency?

90 Hz

100 Hz

120 Hz

To determine the frequency of a sine wave, you can use the relationship between frequency and period, which is given by the formula:

\[ \text{Frequency (f)} = \frac{1}{\text{Period (T)}} \]

In this case, the period (T) is provided as 0.0083 seconds. Plugging this value into the formula, you can calculate the frequency as follows:

\[ f = \frac{1}{0.0083 \text{ seconds}} \]

Calculating the above expression:

\[ f \approx 120 \text{ Hz} \]

Thus, the frequency of the sine wave is 120 Hz. This indicates how many cycles the wave completes in one second. Understanding this relationship is fundamental in fields involving waveforms, electronics, and signal processing. The correct answer, indicating a frequency of 120 Hz, aligns with the calculation you performed using the period.

NEIEP Mechanics Practice Exam

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